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Allisa [31]
2 years ago
14

One-fifth of the sum of 7 and b minus the product of 4 and m​

Mathematics
1 answer:
deff fn [24]2 years ago
4 0

Answer:

7/5 + b/5 - 4m

Step-by-step explanation:

(1/5)(7 + b) - (4)(m) = 7/5 + b/5 - 4m

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Ann, Chang, and Kareem sent a total of
Gnoma [55]

It is given in the question that

Ann, Chang, and Kareem sent a total of 89 text messages over their cell phones during the weekend. Ann sent 9 fewer messages than Chang. Kareem sent 3 times as many messages as Ann.

Let number of messages Chang sent be x. And Ann sent 9 fewer than Chang, so Ann sent (x-9) messages. And Kareem sent 3 times as many messages as Ann, so Kareem sent 3(x-9) messages.

And the total messages are 89. That is

x+x-9+3(x-9)=89

Combining like terms

x + x - 9 + 3x-27 =89
\\
5x -36=89
\\
5x = 125
\\
x =25

So Chang sent 25 messages, Ann sent

25-9=16 messages

And Kareem sent

3*16 = 48 messages

8 0
3 years ago
What the rate of change for f(t)=70(5/2)^t<br> help
denis23 [38]
5/2
70 is the constant number that doesn’t change, but anytime you increase t you are raising it above 5/2. So every time you grow 5/2.
3 0
2 years ago
a spherical snowball is melting in such a manner that its radius is changing at a constant rate, decreasing from 27 cm to 17 cm
Phoenix [80]

Answer:

3.30=90

17/1=17

90+17=107

Step-by-step explanation:

7 0
2 years ago
PLEASE AND THANK YOU CONFUSED ON THIS
ICE Princess25 [194]

After staring at this for a few seconds, I think the equation

-5\sqrt{10}\cdot\sqrt{15}=[1]\sqrt{[2]}

is asking you to simplify the left hand side so that it has a form matching the right hand side, and [1] and [2] are placeholders. My guess is that they're supposed to be integers.

Notice that

\sqrt{10}=\sqrt{5\cdot2}=\sqrt5\cdot\sqrt2

\sqrt{15}=\sqrt{5\cdot3}=\sqrt5\cdot\sqrt3

\implies\sqrt{10}\cdot\sqrt{15}=(\sqrt5)^2\cdot\sqrt2\cdot\sqrt3=5\sqrt{2\cdot3}=5\sqrt6

Then multiplying by -5, we have

-5\sqrt{10}\cdot\sqrt{15}=-25\sqrt6

so I believe [1] = -25, and [2] = 6.

5 0
3 years ago
12 in A 4 in. 1 3 in. 7 in.​
Strike441 [17]
I’m not sure I understand your question
4 0
3 years ago
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