You have to distribute 5 to everything in the parenthesis.
5(2y-7x)
10y-35x
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
Step-by-step explanation:
2/4(9) + 8
2/36 +8
using l.c.m
2+36(8)
__________
36
2+288=290/36 =8.1
Answer:
we have the expression as;
1/sin u cos u
Step-by-step explanation:
tan u = sin u/cos u
cot u = cos u/sin u
Thus;
sin u/cos u + cos u/sin u
The lcm is sin u cos u
Thus, we have that;
(sin^2 u + cos^2 u)/sin u cos u
But ; sin^2 u + cos^2 u = 1
so we have ;
1/sin u cos u
