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masha68 [24]
3 years ago
15

PLEASE HELP ME. Problem is in the photo

Mathematics
1 answer:
poizon [28]3 years ago
4 0

Answer:

13cm

Step-by-step explanation:

Hope this helps! :)

You might be interested in
Which function describes the arithmetic sequence shown?
Lynna [10]

f(x)= -2x-3

Step-by-step explanation:

Step 1:

Let the sequence given here is -5, -7, -9, -11, -13 ......

Here the first term (a₁) of sequence is -5

And the common difference between the numbers in the sequence is

d= (-7-(-5)) = -7+5 = -2

Let the number of terms be x

Step 2;

To find the sequence function basic arithmetic sequence formula is

aₙ = a₁ + d( x-1)

Applying the values we get

f(X) = -5 + ((-2)(X-1))

on simplification

f(X) = -5 + (-2X+2)

f(X)= -5+2-2X

f(X)= -3-2X

8 0
3 years ago
If there are 350 boys in a school with a total of 800 students, then what percent of the students are girls?
tester [92]

Answer:

56.25%

Step-by-step explanation:

800 - 350 = 450

1% of 800 = 8 (800 divided by 100)

450 divided by 8 = 56.25

4 0
3 years ago
Read 2 more answers
One-half the square of b
enot [183]
A machine produces 240 bolts in 25 minutes. At the same rate how many bolts would be produced in 45 minutes
8 0
3 years ago
Read 2 more answers
Can someone answer it please I really need help please I need it right now I was so frustrating please help and please show work
Eduardwww [97]

Answer:

  2 1/4 yards above sea level

Step-by-step explanation:

The midpoint elevation is the average of the endpoint elevations, their sum divided by 2. When elevation is below sea level, it is represented by a negative number.

  (17 3/4 - 13 1/4)/2 = (4 2/4)/2 = 2 1/4 . . . yards above sea level

8 0
3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
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