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Sliva [168]
2 years ago
13

How do you simplify 3(j-2k)+4 ?​

Mathematics
1 answer:
masha68 [24]2 years ago
5 0

Answer: 3j-6k+4

Step-by-step explanation:

First you have to distribute the 3 to the j and the -2k since they are both in the parentheses. So it would look like (3*j) +(-2k*3)+4 and if you simplify that it is 3j-2k+4. After that there are no like terms so that is your answer.

You might be interested in
(4/7) to the second power divided by 24/7
ivolga24 [154]

Answer:

2/21

Step-by-step explanation:

you square 4/7 to get 16/49 then use keep change flip

you now have 16/49 times 7/24 then multiply

4 0
2 years ago
. help needed please​
Anastasy [175]
In order to do this, we would use order of operations. First, Parentheses, which is division with fractions, so we would do KCF,keep it, change it, flip it. keep the first fraction, change the operation to multiplication, then flip the next fraction, making it -7/9 x 3/1. the answer would be -2.33. multiply that by -2, and you would get -4.66, which is your answer. PLEASE MARK BRAINLIEST IF HELPFUL! :))
5 0
3 years ago
What is the lcm of 81 and 17?​
algol [13]

Answer:

1377

Step-by-step explanation:

The least common multiple (LCM) of two or more non-zero whole numbers is the smallest whole number that is divisible by each of those numbers. In other words, the LCM is the smallest number that all of the numbers divide into evenly.

3 0
2 years ago
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
The hypotenuse of a right triangle measures 18 cm and one of its legs measures 12 cm. Find the measure of the other leg. If nece
Serggg [28]

Answer:

16 cm

Step-by-step explanation:

A right triangle, with the hypotenuse = 18, one side = 7, and the other side = x.

Since this is a right triangle, use the pythagorean theorem to find the value for x.

let a = 7 for one side, and let c = 18 for the hypotenuse. And, let c = x for the other side.

The pythagorean theorem is: c^2 = a^2 + b^2.

18^2 = 7^2 + x^2324 = 49 +x^2

x^2 = 324 - 49 = 275So, x = sqrt(275) = 16.5 cm

3 0
2 years ago
Read 2 more answers
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