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Mathematics

2 answers:

Oliga [24]3 years ago

8 0

Answer:

$x \times x + x \times 4 + x \times x + x \times 1 - 3 \times x + 3 \times 4 + 3 \times x + 3 \times 1$

gregori [183]3 years ago

6 0

Answer:

D. (x-3)(x-3)(x-1)

Step-by-step explanation:

(x³-7x²+15x-9)/(x-3) = x²-4x+3<em> (see attached)</em>

x²-4x+3=(x-1)(x-3) <em>(factorisation)</em>

∴x³-7x²+15x-9=(x-3)(x-3)(x-1)

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(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values

Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

$y=t^2 = (x)^2 = x^2$