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Akimi4 [234]
3 years ago
10

1/5 of 20

Mathematics
2 answers:
Rus_ich [418]3 years ago
5 0
1/5 of 20 = 4
1/5 of 35 = 7
1/5 of 25 = 5
1/5 of 10 = 2
1/5 of 500 = 100

Method 1: 1/5 of 20 is 1/5 times 20 which you can solve for by multiplying the 1 by 20 and then dividing by 5 so 20/5=4.

Method 2: 1/5 of 20 is 1/5 times 20 so what you can do is automatically look at it and say that 5 is divisible by 20 and so using the cross method you can eliminate the 1 and just do 20/5=4.

You can either of the processes to figure out all of them.

BigorU [14]3 years ago
3 0
1/5 of 20 is 4.

1/5 of 35 is 7.

1/5th of 25 is 5.

1/5 of 10 is 2.

1/5 of 500 is 100.
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In AHIJ, the measure of ZJ=90°, IJ = 5 feet, and JH = 3.2 feet. Find the measure of
Dominik [7]

Answer:

32.6

Step-by-step explanation:

opp/adj = 3.2/5

I= tan -1(3.2/5)

I =32.6192

=32.6

3 0
3 years ago
Help me please I need the answer ASAP
ozzi

a

10.95x + 2.50, but for eight books so 10.95 x 8 + 2.50 = 90.10

b

12.50x + 4.50, but for six books so 12.50 x 6 + 4.50 = 79.50

c

To do this, we can set them both equal to each other and if x is a whole number of books, then they do pay the same amount. If x is a decimal, then they don't pay the same amount.

10.95x + 2.50 = 12.50x + 4.50

2.50 - 4.50 = 12.50x - 10.95x

-2 = 1.55x

This can never be a whole number, so therefore members and non-members can never pay the same amount for an order of x books.

8 0
4 years ago
PLS HELP ME PLSS AND SHOW HOW YOU GOT YOUR ANSWER
ioda

Answer:

Step-by-step explanation:

3 0
3 years ago
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
4 years ago
9 &lt; 4(x+9) -7 - 25<br> Solve , intervals, and graph
Zigmanuir [339]

Answer:

x> 5/4

Step-by-step explanation:

9<4(x+9)−7−25

Step 1: Simplify both sides of the inequality.

9<4x+4

Step 2: Flip the equation.

4x+4>9

Step 3: Subtract 4 from both sides.

4x+4−4>9−4

4x>5

Step 4: Divide both sides by 4.

4x/4>5/4

x>5/4

pls give brainliest

5 0
3 years ago
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