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emmasim [6.3K]
3 years ago
9

Conjugate base and acid of HS-

Chemistry
1 answer:
kvasek [131]3 years ago
8 0

Answer:

H2S Acid and Base-2

Explanation:

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Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq)→ Cu3(PO4)2(s)+6NaCl(aq)
Troyanec [42]

Answer:

V= 37.0 mL

Explanation:

First find the moles of the known substance (CuCl2)

n= cv

where

n is moles

c is concentration

v is volume ( in litres)

n= 0.108 × 0.0946

n=0.0102168

Using the mole ratio in the balanced reaction, we can find the moles of Na3PO4

n (Na3PO4)= n (CuCl2) × 2/3

=0.0102168 × 2/3

=0.0068112

Now we have all the necessary values to calculate the volume

v=n/c

v= 0.0068112/0.184

v= 0.0370173913 L

v= 37.0 mL

6 0
4 years ago
Solution A has a pH of 3 and solution Z has
igor_vitrenko [27]
PH of a solution is -ln[H3O+] so,in case of A pH=3 or,-log[H3O+]=3 or,[H3O+]=10^-3 in case of B pH=6 pr,-log[H3O+]=6 or, [H3O+]=10^-6 so,hydronium ion concentration in solution A /the hydronium ion concentration in solution Z =10^-3/10^-6 =1000 2) Ca(OH)2+2 HNO3=Ca(NO3)2+2 H2O so the answer is 2.
5 0
4 years ago
Read 2 more answers
Somebody please help me!!
mariarad [96]

Answer:

The given isotope is Br 80

If 35 protons present then its atomic number is 35

Mass number is 80 so its meutrons are 45 because proton+ neutron = mass number

Its electron are 36 because of negative one charge

Explanation:

4 0
3 years ago
WW
SVETLANKA909090 [29]
11 is the answer hope that helps
4 0
3 years ago
How many moles are in 90g of NaOH
Simora [160]

So,

To find the number of moles in 90g of NaOH, what we do is to divide the given amount by the molar mass of NaOH.

The molar mass of NaOH is 40g/mol.

So,

\frac{90gNaOH}{\frac{40gNaOH}{mol}}=2.25\text{ moles of NaOH}

Therefore, the correct answer is A. 2.25moles

5 0
1 year ago
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