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Andrews [41]
3 years ago
15

PLEASE HELP ASAP!!!! I AM BEGGING YOU!

Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer: Standard, and 65,000 its easy as that

Step-by-step explanation:

Hope this helps

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In the following diagram, parallelogram ABCD contains triangle CED. Line CE and line ED intersect at point E. The measures of ∠C
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∠x = 59°

Step-by-step explanation:

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2 years ago
Amanda's school is due west of her house and due south of her friend Shereen's house. The distance between the school and Sheree
Blizzard [7]

The Amanda's house is 6.7 km far from her school.

<u>Step-by-step explanation:</u>

From the given information,

  • The Amanda's school is due west of her house forms the base.
  • The school is due south of the Shereen's house forms the height.
  • The straight-line distance between Amanda's house and Shereen's house forms the hypotenuse.

Therefore, It can be determined that it forms the right angle triangle.

It is given that,

The distance between the school and Shereen's house is 2 kilometers.

That is, the height of the triangle = 2 km

The straight-line distance between Amanda's house and Shereen's house is 7 kilometers.

That is, the hypotenuse of the triangle = 7 km

Now, the distance between the Amanda's house and her school is the base of the triangle.

<u>To find the base :</u>

Base = \sqrt{(hypotenuse)^{2}-(height)^{2}  }

⇒ \sqrt{(7)^{2} -(2)^{2} }

⇒ \sqrt{49-4}

⇒ \sqrt{45}

⇒ 6.7 km

Therefore, the Amanda's house is 6.7 km far from her school.

3 0
3 years ago
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