Find the value of x in the proportion. Check your answer.

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

bagirrra123 [75]

Answer:

$27\pi \ cm^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=6\ cm$

substitute

$A=\pi (6)^{2}=36 \pi\ cm^{2}$

Remember that a central angle of $360\°$ subtends for the area of a complete circle

so

by proportion

Find the area of the circle for a central angle of $270\°$

$\frac{36 \pi}{360} \frac{\ cm^{2}}{degrees}=\frac{x}{270} \frac{\ cm^{2}}{degrees} \\ \\ x=270*36\pi /360\\ \\x=27\pi \ cm^{2}$

5 0

3 years ago

Read 2 more answers

Find the equation of a line that passes through the points (4,0) and (2,4).

Ksju [112]

Answer:

answer is y=-2x+8 is the eq of given line

3 0

2 years ago

2. Us i ng the filled table above,

VARVARA [1.3K]

The price elasticity of demand of the pen will be -0.2.

<h3>How to compute the elasticity?</h3>

The demand and supply schedule will be:

Price Qd. Qs

$10. 250. 100

$20. 200. 90

$30. 180. 80

The price elasticity of demand from $1 to $2 will be:

= Percentage change in quantity demanded/percentage change in price

Percentage change in quantity demanded will be:

= (200 - 250)/250 × 100

= -20%

Percentage change in price will be:

= (20 - 10)/10 × 100

= 100%

Therefore, the elasticity of demand will be:

= -20/100

= - 0.2

The value gotten illustrates an inelastic demand.

In order to increase the total revenue, the price can be reduced as it will lead to more sales.

Learn more about PED on:

brainly.com/question/21105870

#SPJ1

<u>Complete question:</u>

Choose any product or service. Create the demand and supply schedule.

Calculate just one PED.

Is the demand elastic or inelastic?

What price change would you recommend to increase TR?

8 0

2 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$