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algol [13]
3 years ago
11

Please help me with this

Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Answer:

ok

Step-by-step explanation:

ok

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Which sentence about the division of two fractions is true? A. If the dividend is greater than the divisor, the quotient will be
slavikrds [6]

Answer:

A. If the dividend is greater than the divisor, the quotient will be greater than 1.

Step-by-step explanation:

Checking all options

A. If the dividend is greater than the divisor, the quotient will be greater than 1.

That is,

4 ÷ 3 = 1.33

Where,

4 is the dividend

3 is the divisor

1.33 is the quotient

THIS IS TRUE

B.If the dividend is less than the divisor, the quotient will be greater than 1

That is,

3 ÷ 4 = 0.75

Where,

3 is the dividend

4 is the divisor

0.75 is the quotient

NOT TRUE

C. If the dividend is equal to the divisor, the quotient will be less than 1

That is,

3 ÷ 3 = 1

Where,

3 is the dividend

3 is the divisor

1 is the quotient

NOT TRUE

D. If the dividend is greater than the divisor, the quotient will be less than 1.

That is,

4 ÷ 3 = 1.33

Where,

4 is the dividend

3 is the divisor

1.33 is the quotient

NOT TRUE

Therefore, option A is TRUE

6 0
3 years ago
Can you please help me asp because I am really confuse !. Plus you get 14 points!!
djyliett [7]

Answer:

1. B

2. 2 and 1/8 cups

Step-by-step explanation:

You just had to make common denominators and then your would subtract

8 0
3 years ago
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How do you calculate the lateral area??
harkovskaia [24]
Lateral area of cube= LA= 4s^2
Cylinder= LA = 2 x pi x r x h<span>
Prism= LA = p x h</span><span>
</span>and there are many others.. 
3 0
3 years ago
The product of x and 9 equals 45
adell [148]

Answer:

5

Step-by-step explanation:

because ?*9=45

45÷9=5

4 0
3 years ago
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5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest
laila [671]

It's a quadratic equation in disguise. If you let y=x^{-1}, then y^2=x^{-2}, and we can rewrite the equation as

5y^2-17y+6=0

Solve for y however you like; we get y=\dfrac25 and y=3.

But we want to solve for x, so we have

y=x^{-1}=\dfrac25\implies x=\dfrac52

y=x^{-1}=3\implies x=\dfrac13

5 0
3 years ago
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