Consider the cross-sectional right triangle shown in the figure.
One of its sides is the height of the pyramid, with length H. The other side is half of the square base, so its length is 81 m. The hypotenuse of this triangle is the height of one of the faces.
By right triangle trigonometry,
,
thus,
.
Answer: C) 52 m
66/35 = Improper Fraction
66 - 35 = 31
So, 66 can go in 31 1 time.
So 1 will be our whole number. 31 will be d numerator and 35 will be d denominator.
1 31/35
So, 66/35 in mixed number is 1 31/35.
Hope I helped ya!!! xD
Answers: D for it represents the diameter and A for represents the radius
9514 1404 393
Answer:
- arc BC = 60°
- m∠ADC = 60°
- m∠AEB = 105°
- m∠ADP = 45°
- m∠P = 60°
Step-by-step explanation:
The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...
CB : BA : AD : DC = 2 : 2 : 3 : 5
The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...
arc BC = arc BA = 60° . . . . 2 ratio units each
arc AD = 90° . . . . . . . . . . . . 3 ratio units
arc DC = 150° . . . . . . . . . . . .5 ratio units
The inscribed angles are half the measure of the intercepted arcs:
∠ADC = (1/2) arc AC = 1/2(120°) = 60°
∠ADP = 1/2 arc AD = 1/2(90°) = 45°
The angles at E are half the sum of the measures of the intercepted arcs.
∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°
Angle P is half the difference of the intercepted arcs.
∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°
__
In summary, ...
arc BC = 60°
m∠ADC = 60°
m∠AEB = 105°
m∠ADP = 45°
m∠P = 60°
Answer:
-4
Step-by-step explanation:
