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3 years ago

ok ppl i have a lot of missing Assignments so pls do not take my points and i will report any unnecessary comments

Mathematics

2 answers:

valentina_108 [34]3 years ago

6 0

Answer:

Emancipation Proclamation, Reconstruction, secession, equal protection, due process

Step-by-step explanation:

Musya8 [376]3 years ago

4 0

Yes the answer above me is right I have done this worksheet and I got them all right from this

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Find The Area Of The Shape Shown Below

ruslelena [56]

Answer:42.55

Step-by-step explanation:

Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many 2's. So total is 33.5 so far. Next triangle is 2 by 5 soo 10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5

8 0

3 years ago

Read 2 more answers

PLEASE HELP FAST!!!!!!

raketka [301]

The answer is 120 degrees

3 0

3 years ago

Please help me:

Tasya [4]

Answer:

6 units

Step-by-step explanation:

This coordinate is a three dimensional coordinate, which involves positive and negative x,y, and z axis.

The y axis is from left to right, i.e from negative to positive.

So 6 unit left is = -6 but it explains moving left .

Thank you

3 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .