Question

10. A wire is of length 264 cm. It is bent into a circle. What is the radius of the circle so obtained. If it

Answer 1

Answer:

$r = 42$ --- radius

$L = 66$ -- Length of the square

Step-by-step explanation:

Given

$Length = 264cm$

Solving (a): Find the radius (when it formed a circle).

The length of the wire represents the circumference (C) of the wire.

So, we have:

$C = 2\pi r$

Make r the subject

$r = \frac{C}{2\pi}$

Substitute 264 for C

$r = \frac{264}{2\pi}$

$r = \frac{132}{\pi}$

Take $\pi$ as 22/7

$r = \frac{132}{22/7}$

$r = \frac{132*7}{22}$

$r = \frac{924}{22}$

$r = 42$

Solving (b): Find the side length (when it formed a square).

The length of the wire represents the perimeter (P) of the wire.

So, we have:

$P = 4L$

Make L the subject

$L = \frac{1}{4}P$

Substitute 264 for P

$L = \frac{1}{4}*264$

$L = 66$