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3 years ago

Find the Area of the figure below, composed of an isosceles trapezoid and one

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

Area of given figure = 48.28 unit² (Approx.)

Step-by-step explanation:

Given:

Length of parallel lines are 10 , 4 respectively

Diameter of semi-circle = 4

Height of parallelogram = 6

Find:

Area of given figure

Computation:

Radius of semi-circle = Diameter of semi-circle / 2

Radius of semi-circle = 4 / 2

Radius of semi-circle = 2

Area of given figure = [1/2][Sum of parallel line][Height] + [πr² / 2]

Area of given figure = [1/2][10 + 4][6] + [(3.14)(2)² / 2]

Area of given figure = [1/2][14][6] + [(3.14)(4)/ 2]

Area of given figure = 42 + 6.28

Area of given figure = 48.28 unit² (Approx.)

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vekshin1

Answer:

that's it I think its clear

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4 years ago

A small town has two local high schools. High School A currently has 800 students and is projected to grow by 55 students each y

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3 years ago

Can someone please help me I’ve tried so many ways and still can’t get the answer.

mr Goodwill [35]

Answer:

15.22

Step-by-step explanation:

The equation of the circumference of a circle is 2(pi)r

This is actually because 2pi is angle of the arc that makes up the full circle (radians of course)

so a simple formula is:

arc length in radians X radius

radius = 4 cm

the area that the question wants is the oposite

of the 142 degree section so 360 - 142 = 218

218 degrees * (pi/180) = 3.80482 rad

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3 0

3 years ago

Help maybe , please ??

vaieri [72.5K]

Step-by-step explanation:

x + 53 = 90

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answer is 37

5 0

4 years ago

Read 2 more answers

The ages (in years) and weights (in pounds) of all wide receivers for a football team are listed. Find the coefficient of variat

IceJOKER [234]

Answer:

The coefficient of variation for the weight and age are 5.9% and 10.6%.

Step-by-step explanation:

The coefficient of variation (CV) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.

The formula to compute the coefficient of variation is:

$CV=\frac{\sigma}{\mu}\times 100\%$

Here σ = standard deviation and µ = mean.

Compute the mean and standard deviations of the two data set in Excel using the following functions.

Mean=AVERAGE()

Standard deviation=STDEV.S()

Consider the Excel sheet attached.

The mean and standard deviation of weight are:

Mean = 202, Standard deviation = 11.87

And the mean and standard deviation of weight are:

Mean = 25.88, Standard deviation = 2.75

Compute the coefficient of variation for the weight as follows:

$CV_{weight}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{11.87}{202}\times 100\%\\\\=5.87624\\\\=5.9\%$

Compute the coefficient of variation for the age as follows:

$CV_{age}=\frac{\sigma}{\mu}\times 100\%$

$=\frac{2.75}{25.88}\times 100\%\\\\=10.62597\\\\=10.6\%$

Thus, the coefficient of variation for the weight and age are 5.9% and 10.6%.

8 0

3 years ago