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3 years ago

Find the Area of the figure below, composed of an isosceles trapezoid and one

Mathematics

1 answer:

lukranit [14]3 years ago

6 0

Answer:

Area of given figure = 48.28 unit² (Approx.)

Step-by-step explanation:

Given:

Length of parallel lines are 10 , 4 respectively

Diameter of semi-circle = 4

Height of parallelogram = 6

Find:

Area of given figure

Computation:

Radius of semi-circle = Diameter of semi-circle / 2

Radius of semi-circle = 4 / 2

Radius of semi-circle = 2

Area of given figure = [1/2][Sum of parallel line][Height] + [πr² / 2]

Area of given figure = [1/2][10 + 4][6] + [(3.14)(2)² / 2]

Area of given figure = [1/2][14][6] + [(3.14)(4)/ 2]

Area of given figure = 42 + 6.28

Area of given figure = 48.28 unit² (Approx.)

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This answer maybe long, but it includes all the essential steps to make it easy
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