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Trava [24]
3 years ago
8

Tyreek Hill is the fastest player in the NFL, running a 40 yar dash in 2.4 seconds. Using the rate, 38 yards for every 4 seconds

: How many yards can he run in 12 seconds?
Mathematics
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

He can run 112 yards in 12 seconds

Step-by-step explanation:

Here, we want to know the number of yards he can run in 12 seconds

From the question, we are told that his running rate is 38 yards in 4 seconds

So the number of yards he can run in 12 seconds will be;

38 * 12/4

= 38 * 3 = 114 yards

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makvit [3.9K]
The answer is A. y = -2/5
4 0
3 years ago
High expression is equivalent to ^4 square root x^10
Talja [164]

In order to find which <u>expression</u> is <u>equivalent</u> to \sqrt[4]{x^{10}}, <u>simplify</u> all given expressions:

0.

\sqrt[4]{x^{10}}=x^{\frac{10}{4}}=x^{\frac{5}{2}}=x^{2.5}.

1.

x^2(\sqrt[4]{x^2})=x^2\cdot x^{\frac{2}{4}}=x^2\cdot x^{\frac{1}{2}}=x^2\cdot x^{0.5}=x^{2.5}.

2.

x^{2.2}.

3.

x^3(\sqrt[4]{x} )=x^3\cdot x^{\frac{1}{4}}=x^3\cdot x^{0.25}=x^{3.25}.

4.

x^5.

Therefore,

Answer: correct choice is A

7 0
4 years ago
I will give 50 points and brainliest ​
Kay [80]

Answer:

27.2mm²

Step-by-step explanation:

Area of a triangle = \frac{1}{2} * base * height

Base of this triangle = 8mm

Height = 6.8mm

Area = \frac{1}{2} * 8mm * 6.8mm

       = 4mm * 6.8mm

       = 27.2mm²

6 0
3 years ago
Read 2 more answers
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
The first performance of the school play sold out for all 2000 tickets. The tickets sales receipts totaled$8500. If adults paid
azamat
A+s=2000
5a+3s=8500
a=-s+2000
-5s+10000+3s=8500
-2s=-1500
s=750
a=1250
They sold 750 student tickets and 1,250 adult tickets
8 0
3 years ago
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