All categories

2 years ago

3) Given that lines a and b are parallel, and lines o and t are parallel, find the point

Mathematics

1 answer:

Crazy boy [7]2 years ago

3 0

Answer:

X = 3°

Step-by-step explanation:

Since O and T are parallel you can use alternating lines

7x + 5° = 5x + 11° (alt. angles, O||T)

Move the 5x and the 5°

7x - 5x = 11° - 5°

2x = 6°

Divide both sides by 2

x = 3°

This is assuming 11 is an angle

You might be interested in

A car’s stopping distance in feet is modeled by the equation d(v)=2.15vsquared over 58.4f, where v is the initial velocity of th

frutty [35]

According to your description, you can simply plug in all the numbers:

d(47) = 2.15 * 45^2 / (58.4*0.34) = 219.27 m

3 0

3 years ago

Read 2 more answers

Please answer. I’ll mark brainlist

FromTheMoon [43]

Answer: the answer is the first one!!

Step-by-step explanation: split the shape up and multiple the numbers that came with the problem and then put all the totals together i got a total of 364!! Hope that helps!!

7 0

3 years ago

Read 2 more answers

How can i find the answer to this?

ale4655 [162]

Answer:

Step-by-step explanation:

by the property of corresponding angles (2x +16) and (3x-12) will be equal

working uot from the equation 3x-12 = 2x+16 we get x=28

and we know that 3x-12 and y are supplementry as they form a linear pair

from that we will get the equation - 3x-12 + y = 180 and we know the value of x sowe will get y as 108

8 0

2 years ago

12. How much do 21 bushels of sweet

lesantik [10]

Answer:

21 bushels of sweet corm weight 735 pounds.

Step-by-step explanation:

Given:

Weight of 21 bushels of sweet corn is obtained by multiplying the unit weight to the number of bushels required.

Unit weight of sweet corn is the weight of 1 bushel of sweet corn.

Weight of 1 bushel of sweet corn = 35 pounds

So, weight of 21 bushels of sweet corns = $35\times 21=735$ pounds.

Therefore, 21 bushels of sweet corn weigh 735 pounds.

8 0

3 years ago

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

Oxana [17]

Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$

5 0

2 years ago