Well, so the x+5y= 0 you can make this into x=-5y and then plug this in into ( y=9-2x) the -2x , which these would become y=9-2(-5y) simplify and equals to y=9+10y. Then you simplify much smaller y=-9. Now that you have the y number you just plug this in into x=-5y, which these becomes x=-5(-9) and the answer is x=45. At the end you just need to find the x and y, so the answer is x=45 and y=-9 . Hopefully this would make this much easier to you.
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.
b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer:
Exact form : 3/10
Decimal form : 0.3
Step-by-step explanation: To subtract fractions, find the LCD (Least Common Denominator) and then combine.
Hope this helps you out! If you need anymore help with math, let me know and I will be more than happy to help you out! ☺
-Karleif Jonsi-
5. 5x-5
. ------------------
. 10x²-25x+15
We can first factor 10x²-25x+15, it will turn into (2x-3) and (5x-5)
(if you need help on factoring, please leave a comment)
So the question will be like:
. 5x-5
. ---------------
. (2x-3)(5x-5) The factored answer is the same as the original . number, so the factor answer can replace it.
We know 5x-5 on the top and 5x-5 on the bottom is the same, so they can cancel out, and it will become:
2x-3=0
Then solve
2x-3=0
2x=3
x=2/3
6.
Hope this helps! Please give me the Brainliest answer if you like it! If you have further questions, you can leave a comment or add me as a friend!
(if you need more explanations, please leave a comment)