Answer:
Step-by-step explanation:
Answer:
answer down below:
https://vsa.flvs.net/default.aspx?PageID=117&fn=Student-Dashboard
Step-by-step explanation:
Why not actually graph |x|=1? You will find that x = 1 and x = -1 are solutions.
Thus, "closed circles on -1 and 1 with no line" is correct.
B. 2
Real zero is where a graph crosses x-axis. In this case it crosses it two times
Solve by Factoring x^(2/3)-7x^(1/3)+10=0
x
2
3
−
7
x
1
3
+
10
=
0
x
2
3
-
7
x
1
3
+
10
=
0
Rewrite
x
2
3
x
2
3
as
(
x
1
3
)
2
(
x
1
3
)
2
.
(
x
1
3
)
2
−
7
x
1
3
+
10
=
0
(
x
1
3
)
2
-
7
x
1
3
+
10
=
0
Let
u
=
x
1
3
u
=
x
1
3
. Substitute
u
u
for all occurrences of
x
1
3
x
1
3
.
u
2
−
7
u
+
10
=
0
