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lorasvet [3.4K]
2 years ago
12

The dot plots below show the age of some dance students and some yoga students: Two dot plots are shown one below the other. The

top and the bottom plots have the title Dance Students and Yoga Students respectively. Below the line for each dot plot is written Age followed by years in parentheses. The markings on each line are from 10 to 30 at intervals of 1. For the top plot there are two dots for 13 and 16 and 1 dot each for 12, 15, 17, 18, and 20. For the bottom plot there are 2 dots for 25 and 1 dot each for 17, 19, 20, 22, 24, 27, and 29. Based on visual inspection of the dot plots, which group of students appears to have the larger average age? The yoga students The dance students Both groups are similar. Not enough information is available to draw a conclusion.
Mathematics
2 answers:
satela [25.4K]2 years ago
8 0

Answer:

Yoga Students

Step-by-step explanation:

Hope this helped! ✪ ω ✪

11Alexandr11 [23.1K]2 years ago
7 0

Answer:

The yoga students

Step-by-step explanation:

This one is kinda easy but i took the test and got it right have a good day! :)

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Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab
Nastasia [14]

Answer:

1/12

Step-by-step explanation:

<u>Needed information</u>

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

The sum of the probabilities of all outcomes must equal 1

<u>Solution</u>

We are told that the probability that the counter is <em>not</em> black is 3/4.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>black by subtracting 3/4 from 1:

\sf P(counter\:not\:black)=\dfrac34

\implies \sf P(counter\:black)=1-\dfrac34=\dfrac14

We are told that the probability that the counter is <em>not </em>white is 2/3.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>white by subtracting 2/3 from 1:

\sf P(counter\:not\:white)=\dfrac23

\implies \sf P(counter\:white)=1-\dfrac23=\dfrac13

We are told that there are black, white and grey counters in the bag.  We also know that the sum of the probabilities of all outcomes must equal 1.  Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}

7 0
2 years ago
The sum of two numbers is 70. one number is 4 times as large as the other. What are the numbers?
FinnZ [79.3K]

One number is 4 times the other, so x and 4x.

The sum of two numbers is 4x+x=70.

Solve for x to get

x=70/5=14

the other number is 4x=4*14=56

4 0
3 years ago
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snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

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BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



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