Help me out with the correct answer!!!!!
2 answers:
9^2 + 40^2 = 41^2
(The dark blue box is the correct answer)
1.) Figure out what is 9^2 and 40^2
9 * 9 = 81
40 * 40 = 1600
2.) Now add those two numbers together
1600 + 81 = 1681
3.) Find the square root of 1681
√1681 = 41^2
And that’s how to figure out if a triangle is a right triangle. Hope this helped :D
Answer:
yellow i think
Step-by-step explanation:
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Answer:
2 RootIndex 4 StartRoot 4 EndRoot
Step-by-step explanation:
we have
Decompose the number 64 in prime factors
substitute
![64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%282%5E%7B4%7D2%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D2%5E%7B%5Cfrac%7B4%7D%7B4%7D%7D2%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
Answer:
9 if I am correct also I rounded to a whole number, am not sure
Answer: y=-1/2x-4
Step-by-step explanation:
If you use point slope formula you get
y+2=-1/2(x+4)
simplify that in y=mx+b and you get
y=-1/2x-4
Two less than 5 times a number is 9
