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mars1129 [50]
2 years ago
8

Help me out with the correct answer!!!!!

Mathematics
2 answers:
rosijanka [135]2 years ago
5 0
9^2 + 40^2 = 41^2
(The dark blue box is the correct answer)


1.) Figure out what is 9^2 and 40^2
9 * 9 = 81
40 * 40 = 1600

2.) Now add those two numbers together
1600 + 81 = 1681

3.) Find the square root of 1681
√1681 = 41^2

And that’s how to figure out if a triangle is a right triangle. Hope this helped :D
tester [92]2 years ago
3 0

Answer:

yellow i think

Step-by-step explanation:

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The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

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3 years ago
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vfiekz [6]
6x-9=15
6x=24
x=4
Therefore the answer is A.

Hope this helps :)
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3 years ago
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What is the answer to. 4x + 7&lt;8
sukhopar [10]
First, subtract 7 on both sides. Now, you have 4x<1. Divide by 4 on both sides. Finally, you get x<1/4 (a quarter or said as one-fourth). So, x<1/4.
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Solve the value of x 5(2x+1)​
Margaret [11]
The value of x is -1/2

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