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allsm [11]
3 years ago
15

Please help!!!!!! i really need it thanks.

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

Answer:

number 1 is d

number 2 is c

kotykmax [81]3 years ago
5 0
I I can’t even see the question
Sorry
Can’t answer
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Find the inflection point of the function of f(x) = x³ -6x² +12x
Wewaii [24]

Points of inflections are zeroes of the second derivative. We have:

f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12

So, the second derivative equals zero if and only if

f''(x)=0\iff 6x-12=0 \iff 6x=12 \iff x=2

So, this is the only point of inflection of this function.

5 0
3 years ago
​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$17 comma 90017,900
Vedmedyk [2.9K]

Answer:

In 17th year, his income was $30,700.

Step-by-step explanation:

It is given that the income has been increasing each year by the same dollar amount. It means it is linear function.

Income in first year = $17,900

Income in 4th year = $20,300

Let y be the income at x year.

It means the line passes through the point (1,17900) and (4,20300).

If a line passes through two points (x_1,y_1) and (x_2,y_2), then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-17900=\frac{20300-17900}{4-1}(x-1)

y-17900=\frac{2400}{3}(x-1)

y-17900=800(x-1)

y-17900=800x-800

Add 17900 on both sides.

y=800x-800+17900

y=800x+17100

The income equation is y=800x+17100.

Substitute y=30,700 in the above equation.

30700=800x+17100

Subtract 17100 from both sides.

30700-17100=800x

13600=800x

Divide both sides by 800.

\frac{13600}{800}=x

17=x

Therefore, in 17th year his income was $30,700.

5 0
3 years ago
9/10-1/3-1/5 find the fraction
Zanzabum
Find a common multiple in between the denominators.
10 and 3 and 5 -> the least common multiple is 30.

Change all the denominators to 30 by multiplying the top and bottom by the same number.

9/10=27/30
1/3=10/30
1/5=6/30

Subtract!
27/39-10/30-6/30=11/30

The answer is 11/30

Hope this helps!



3 0
3 years ago
Solve the following automotive-services problems based on the examples shown previously. Choose the correct answer.
Radda [10]
Transmission must be in third gear as both are running at the same speed ! so third gear !!!
7 0
3 years ago
Read 2 more answers
What is the second term of (p+q)^5<br> 1. 25p^4<br> 2. 5p^4q<br> 3. 25p^4q<br> 4. 125p^4q
yaroslaw [1]
I hope this helps you

4 0
3 years ago
Read 2 more answers
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