Answer:
8/12
Step-by-step explanation:
Answer:
<u>475 runners</u> competed in the Labor Day race.
Step-by-step explanation:
Given:
Last year, 60% of runners who competed in the Labor Day race finished in 1 hour or less. There were 285 runners who finished the Labor Day race in 1 hour or less.
Now, to find the runners competed in the Labor Day race.
Let the runners competed in the Labor Day race be 
Rate of runners who competed in the Labor Day race finished in 1 hour or less = 60%.
Number of runners who competed in the Labor Day race finished in 1 hour or less = 285.
Now, to get the runners competed in the Labor Day race we put an equation:



<em>Dividing both sides by 0.60 we get:</em>

Therefore, 475 runners competed in the Labor Day race.
Assuming it's a constant rate, there is a four hour difference from t=1 and t=5, so subtract the difference in depth (0.03 - 0.06) and divide that by four.
-0.03/4 = -0.0075
So your change in depth in feet per hour is -0.0075

.
Answer:
x = -6 ; y = -1
Step-by-step explanation:
2 x - y = - 11 .........equ No 1
- 2 x - y = 13 .........equ No 2
Adding equ No. 1 and equ No. 2
- 2 y = 2
∴ y = - 1
substituting y = -1 in equ no 1
2 x - ( -1) = -11
2 x + 1 = - 11
2 x = -11 - 1
2 x = -12
∴ x = -6
x = -6 ; y = -1