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erica [24]
3 years ago
6

I need help with all question, I will give brainliest.

Mathematics
2 answers:
Lemur [1.5K]3 years ago
5 0

Answer:

1) y= 30

2) y - 45

3) y= 60

4) y = 3

Step-by-step explanation:

Alik [6]3 years ago
4 0

Answer:

1. y=30

2. y=45

3. y=60

4. y=3

hope this helps!!!

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the annual yield of mango orchard is 656 565 kg.in the second year,the yield of mango orchard decreased by 100 984 kg.how much m
ELEN [110]

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555581 i think.

Step-by-step explanation:

3 0
3 years ago
HEY CAN SOMEONE DO NUMBER 1 FOR ME ONLY??? ILL GIVE BRAINLIEST!!!!! IM RUSHINGGGGG
kondor19780726 [428]

Answer:

8/12

Step-by-step explanation:

7 0
3 years ago
Last year, 60% of runners who competed in the Labor Day race finished in 1 hour or less. There were 285 runners who finished the
Strike441 [17]

Answer:

<u>475 runners</u> competed in the Labor Day race.

Step-by-step explanation:

Given:

Last year, 60% of runners who competed in the Labor Day race finished in 1 hour or less. There were 285 runners who finished the Labor Day race in 1 hour or less.

Now, to find the runners competed in the Labor Day race.

Let the runners competed in the Labor Day race be x.

Rate of runners who competed in the Labor Day race finished in 1 hour or less = 60%.

Number of runners who competed in the Labor Day race finished in 1 hour or less = 285.

Now, to get the runners competed in the Labor Day race we put an equation:

60\%\ of\ x=285

\frac{60}{100} \times x=285

0.60x=285

<em>Dividing both sides by 0.60 we get:</em>

x=475.

Therefore, 475 runners competed in the Labor Day race.

4 0
3 years ago
A puddle is 0.06 feet deep after 1 hour and 0.03 feet deep after 5 hours. At what rate in
Fed [463]
Assuming it's a constant rate, there is a four hour difference from t=1 and t=5, so subtract the difference in depth (0.03 - 0.06) and divide that by four.

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6 0
3 years ago
2x-y=-11 Y=-2x-13<br> Solve by using elimination
Crazy boy [7]

Answer:

x = -6 ; y = -1

Step-by-step explanation:

2 x - y = - 11   .........equ No 1

- 2 x - y =  13 .........equ No 2

Adding equ  No. 1 and equ No. 2

- 2 y  = 2

∴ y = - 1

substituting y = -1 in equ no 1

2 x - ( -1) = -11

2 x + 1 = - 11

2 x = -11 - 1

2 x = -12

∴ x = -6

x = -6 ; y = -1

8 0
3 years ago
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