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kondor19780726 [428]
3 years ago
15

1 point

Mathematics
2 answers:
Bond [772]3 years ago
8 0
None of the above
Hope this helps you
Klio2033 [76]3 years ago
6 0
None of the above hope this helps :)
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8 pounds 10 ounces of candy from a candy shop split equally among 3 classes how much should each classroom receive
postnew [5]
<span>2.87500 pounds. yup just putting extra characters.</span>
5 0
3 years ago
1. What is the value of the expression<br> 4X (4 – 2) + 6?
Snezhnost [94]

Answer:

8x+6

Step-by-step explanation:

4x (4-2)=2

4X*2+6

8x+6

6 0
4 years ago
Read 2 more answers
The point P has coordinates (-2,6).The point M has coordinates (5,6)
nekit [7.7K]
Find the gradient/slope
6-6/5-(-2) deltaY/deltaX
=0 shows its a straight line
Delta X = 7
Distance between P & M = 7 units
If M is the midpoint then Q is 7*2 units
Away from P (14 units away)
-2 + 14 units = 12 x-coordinate
Hence the coordinates of Q
= (12,6)

FINAL ANSWER:
Coordinates of Q (12,6)
8 0
4 years ago
Find the value of each variable so that PQRS is a parallelogram. Explain what allows you to do this.
Nataly [62]

Answer:

x = 5

y = 16

Step-by-step explanation:

Given

See attachment for parallelogram

Required

Find variables x and y

Solving for x, we have:

5x = 25 ---- Opposite sides of a parallelogram

\frac{5x}{5} = \frac{25}{5} ------ Divide both sides by 5

x = 5

Solving for y, we have:

3y - 1 = 47 ---- Opposite sides of a parallelogram

3y = 1 + 47 ------ Collect like terms

3y = 48

\frac{3y}{3} = \frac{48}{3} ---- Divide both sides by 3

y = 16

4 0
3 years ago
Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10
AnnyKZ [126]

Answer:

a)P=0.42

b) n\geq 297

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}

a) we have k=2, n=10 and p=0.01:

P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42

b) We have, 1-(1-p)^n=P, Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297

4 0
3 years ago
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