The best information we can use is the ratio of defectuosity, 2/150
Applying it to the size of the batch
N=3000*2/150 = 40
Answer: out of the batch of 3000 products, likely 40 products are defective, if the products are drawn from the same production run.
It’s is false I have had this question before
Answer:
Given,
Distance traveled = 20 km
Speed = 60 km/h
So, timetaken=DistanceSpeed=2060=13h
For the next journey
Distance traveled = 20 km
Speed = 80 km/h
So, timetaken=DistanceSpeed=2080=14h
Now,
Total distance traveled = 20 + 20 = 40 km
Total time taken = 13+14=712
We know,
Averagespeed=TotaldistancetraveledTotaltimetaken=40712=68.5 km/h
Hence the average speed of the train is 68.5 km/h
Answer:
38,710.
Step-by-step explanation:
This is an arithmetic series with common difference 8 , first term a = 7 and last term L = 783.
The number of terms n = (783 - 7) / 8 + 1 = 98
Sum of 98 terms = (n/2)[a + L)
= (98/2)(7 + 783)
= 49 * 790
= 38,710.