Question

Divide using common factors. (-4x^3 + 8x^2 – 16x) ÷ (2x)

Answer 1

Answer:

$= \frac{( - 4 {x}^{3} + 8 {x}^{2} - 16x) }{2x} \\ = \frac{ - 4 {x}^{3} }{2x} + \frac{8 {x}^{2} }{2x} - \frac{16x}{2x} \\ = - 2 {x}^{2} + 4x - 8$

Answer 2

Answer: Hello Luv......

Factor the numerator and denominator and cancel the common factors.

−2x2+4x−8

Step-by-step explanation:

Hope this helps. Mark me brainest please.

Anna ♥