When Thomas Jefferson referred to the Missouri Compromise he described it as “ fire bell in the night”. This is because he saw it as a pressing matter and he saw this as an emergency since a fire bell at night indicates that there is an emergency.
Hope this helps! :3
Identity process<span> theory proposes that adjustment to aging can be conceptualized as involving the three </span>processes<span> of identity assimilation (maintaining </span>self<span>-consistency), identity accommodation (making changes in the </span>self<span>), and identity balance (maintaining a sense of </span>self<span> but changing when needed.)</span>
The answer is daily I do believe or either hourly.
You're looking for the 15th percentile of a normal distribution with <em>µ</em> = 242 and <em>σ</em> = 13, which is to say you want to find <em>x</em> * such that
P(<em>X</em> ≤ <em>x</em> *) = 0.15
Transform the wait-time random variable <em>X</em> to <em>Z</em>, which follows the standard normal distribution with mean 0 and s.d. 1 :
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> → <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em> = 242 + 13 <em>Z</em>
Now,
P(<em>X</em> ≤ <em>x</em> *) = P(242 + 13<em> Z</em> ≤ <em>x</em> *) = P(<em>Z</em> ≤ (<em>x</em> * - 242)/13) = 0.15
Use a calculator (something with an inverse CDF function) or <em>Z</em>-table to look up the <em>z</em>-score, <em>z</em> = (<em>x</em> * - 242)/13, associated with a probability of 0.15. You would find that
<em>z</em> = (<em>x</em> * - 242)/13 ≈ -1.03643
Solve for <em>x</em> * :
<em>x</em> * ≈ 242 + 13 (-1.03643) ≈ 228.526 ≈ 229