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2 years ago

Please help!!! Math 10 points!

Mathematics

2 answers:

Anni [7]2 years ago

7 0

Answer:

2nd one would be 20, 3rd one would be 6, 4th one would be 54, and the last one would be 18. hope that helped !

Step-by-step explanation:

If a printer is printing 15 papers in 3 minutes, all you have to do is divide 15 by 3, and you get you answer. The answer would be 5 which you would mulitply by the bottom number or divide by the top number.

zheka24 [161]2 years ago

4 0

Answer:

First Blank: 20 photos

Second Blank: 6 minutes

Third Blank: 45 Photos

Fourth Blank: 10 minutes.

Step-by-step explanation:

4*5=20 Photos

30/5=6 Minutes

9*5=45 Photos

50/5=10 Minutes

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May someone help me out with this please.

Fed [463]

I think The answer is 22.5

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3 years ago

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Solve each quadratic equation. Show your work 15. x2 + 3x = 10

OLEGan [10]

X² + 3x = 10

Convert to standard form.
x² + 3x - 10 = 0

factor x² = x * x
factor -10 = 5 * -2

(x + 5) (x - 2) = 0
x(x -2) + 5(x-2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0

x + 5 = 0   x² + 3x = 10
x = -5 -5² + 3(-5) = 10
25 - 15 = 10
10 = 10

x - 2 = 0 x² + 3x = 10
x = 2 2² + 3(2) = 10
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3 years ago

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Eight less than a number is no more than 14

myrzilka [38]

Answer:

x - 8 ≤ 14

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

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The lengths of two sides of a triangle are 10 and 24, and the third side is x. How many whole number values are possible for x.

solong [7]

Answer:

$20$ .

Step-by-step explanation:

In any triangle, the sum of the lengths of any two sides should be strictly greater than the length of the third side. For example, if the length of the three sides are $a$ , $b$ , and $c$ :

$a + b > c$ ,

$a + c > b$ , and

$b + c > a$ .

In this question, the length of the sides are $10$ , $24$ , and $x$ . The length of these sides should satisfty the following inequalities:

$10 + 24 > x$ ,

$10 + x > 24$ , and

$24 + x > 10$ .

Since $x > 0$ , the inequality $24 + x > 10$ is guarenteed to be satisfied.

Simplify $10 + 24 > x$ to obtain the inequality $x < 35$ .

Similarly, simplify $10 + x > 24$ to obtain the inequality $x > 14$ .

Since $x$ needs to be a whole number, the greatest $x$ that satisfies $x < 35$ would be $34$ . Similarly, the least $x\!$ that satisfies $x > 14$ would be $15$ . Thus, $x\!\!$ could be any whole number between $15\!$ and $34\!$ (inclusive.)

There are a total of $34 - 15 + 1 = 20$ distinct whole numbers between $15$ and $34$ (inclusive.) Thus, the number of possible whole number values for $x$ would be $20$ .

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2 years ago