Area of right-angled triangle is given by;
Area, A = 1/2 *b*h, Where b=base, h=height
Therefore,
A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh
Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2
Answer:
First since 2 of the options ask for the width of BM lets solve for it using the Pythagorean theorem for both sides of point L:
a² + b² = c²
30² + b² = 50²
b² = 50² - 30²
b² = 1600
b = 40 Line BL = 40 ft
Since the ladder is 50 feet it is the same length on the other side as well
a² + b² = c²
40² + b² = 50²
b² = 50² - 40²
b² = 900
b = 30 line LM is 30 ft
SO line lm + line bl = 30 + 40 = 70 ft
A is true because ^
B isn't true because as we solved for earlier, BL is 40
C is true because line LM is in fact 30 ft as we solved for
D is not true because as we said earlier BM is 70
E is true because the same ladder was used on both sides of the street
Step-by-step explanation:
Answer:
x = 65
Step-by-step explanation:
using the Altitude- on- Hypotenuse theorem
(leg of big Δ )² = (part of hypotenuse below it ) × (whole hypotenuse)
x² = 25 × 169 = 4225 ( take square root of both sides )
x = 
= 65
Subtract 2d from both sides
simplify 10 + 2.5d - 2d to 10 + 0.5d
subtract 10 from both sides
simplify 4 - 10 to -6
divide both sides by 0.5
simplify 6/0.5 to 12
switch the sides
Answer: d = -12.
I don’t really understand the question, but if you’re looking for the area, it would be 100 feet since you have to do “Side x Side”. Hope this helps!
