Answer:
120
Step-by-step explanation:
Corresponding angles of similar figures are congruent.
Just add w/ a calculator
10.66 inches
all you have to do is add like normal but line up the decimal points and keep the point in the same place
Answer:
The approximate length of the diagonal walkway is 21.21 meters
Step-by-step explanation:
we know that
Applying the Pythagorean Theorem in the square park, find out the the approximate length of the diagonal walkway
so
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
where
c is the diagonal of the square
a and b are the length sides of the square
we have
![a=15\ m\\b=15\ m](https://tex.z-dn.net/?f=a%3D15%5C%20m%5C%5Cb%3D15%5C%20m)
substitute
![c^2=15^2+15^2\\c^2=450\\c=21.21\ m](https://tex.z-dn.net/?f=c%5E2%3D15%5E2%2B15%5E2%5C%5Cc%5E2%3D450%5C%5Cc%3D21.21%5C%20m)
therefore
The approximate length of the diagonal walkway is 21.21 meters
thye awser should be m<-1/8
Rmember (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)this is just alot of busy work
find f+g first then find f-g
f+g=(x-4)/(x+9)+(x-9)/(x+4)
make denomenator the same
multiply left one by (x+4)/(x+4) and right one by (x+9)/(x+9)
[(x-4)(x+4)]/[(x+9)(x+4)]+[(x-9)(x+9)]/[(x+9)(x+4)]
[x²-16]/[(x+9)(x+4)]+[x²-81]/[(x+9)(x+4)]
[x²+x²-16-81]/[(x+9)(x+4)]
[2x²-97]/[(x+9)(x+4)]
now f-g
[x²-16]/[(x+9)(x+4)]-[x²-81]/[(x+9)(x+4)]
[x²-x²-16+81]/[(x+9)(x+4)]
[65]/[(x+9)(x+4)]
now we got
![\frac{ \frac{2x^2-97}{(x+9)(x+4)} }{ \frac{65}{(x+9)(x+4)} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Cfrac%7B2x%5E2-97%7D%7B%28x%2B9%29%28x%2B4%29%7D%20%7D%7B%20%5Cfrac%7B65%7D%7B%28x%2B9%29%28x%2B4%29%7D%20%7D%20)
invert and multiply
![(\frac{2x^2-97}{(x+9)(x+4)})(\frac{(x+9)(x+4)}{65})](https://tex.z-dn.net/?f=%28%5Cfrac%7B2x%5E2-97%7D%7B%28x%2B9%29%28x%2B4%29%7D%29%28%5Cfrac%7B%28x%2B9%29%28x%2B4%29%7D%7B65%7D%29)
![\frac{2x^2-97}{65}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%5E2-97%7D%7B65%7D%20)
2nd option