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gladu [14]
2 years ago
11

3h - j when h = 8 and j = 11 plzzz help

Mathematics
1 answer:
AURORKA [14]2 years ago
8 0

Answer:

13

Step-by-step explanation:

3h - j

3(8) - 11

24 - 11

13

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Which statement is true for the equation 4n – 3 = 4n – 2 Select one: a. It has no solution. b. It has one solution. c. It has tw
oksian1 [2.3K]
4n-3=4n-2  subtract 4n from both sides

-3=-2 

Since -3!=-2, there is no solution.

So your answer is a.
7 0
3 years ago
Read 2 more answers
-(3/4)+1 7/8 divided by 1/2 =n
VashaNatasha [74]

first off, let's convert the mixed fraction to improper fraction and then proceed, let's notice that by PEMDAS or order of operations, the multiplication is done first, and then any sums.

\stackrel{mixed}{1\frac{7}{8}}\implies \cfrac{1\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{15}{8}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \div \cfrac{1}{2}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \cdot \cfrac{2}{1}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{4} \\\\\\ \cfrac{-3+15}{4}\implies \cfrac{12}{4}\implies 3

5 0
2 years ago
James has a balance of $1700 on a credit card with an APR of 18.7%, compounded monthly. About how much will he save in interest
miss Akunina [59]

Answer:

  $121.51

Step-by-step explanation:

At 18.7%, the monthly multiplier is 1+.187/12, so for the year, James' balance is multiplied by (1+.187/12)^12 ≈ 1.2038899

At 12.5%, the monthly multiplier is 1+.125/12, so for the year, James' balance is multiplied by (1+.125/12)^12 ≈ 1.1324161

The difference in these multipliers is ...

  1.2038899 -1.13241605 = 0.0714739

so James' savings is ...

  $1700 × 0.0714739 ≈ $121.51

5 0
3 years ago
Which equation has infinitely many solutions?
liubo4ka [24]

Answer:

c

Step-by-step explanation:

i dont really have an explanation but i got it right

6 0
3 years ago
Write the explicit formula for the geometric sequence.<br><br> a1 = -5 a2 = 20 a3 = -80
Anni [7]
a_1 = -5;\ a_2 = 20;\ a_3 = -80 \\\\a_2:a_1=r\ and\ a_3:a_2=r\\\\r=20:(-5)=-4\ check\ r=-80:20=-4\\\\a_n=a_1r^{n-1}\to a_n=-5\cdot(-4)^{n-1}=-5\cdot(-4)^{-1}\cdot(-4)^n\\\\=-5\cdot\left(-\dfrac{1}{4}\right)\cdot(-4)^n=\dfrac{5}{4}\cdot(-4)^n\\\\Answer:\boxed{a_n=-5\cdot(-4)^{n-1}\ other\ a_n=\frac{5}{4}\cdot(-4)^n}
6 0
3 years ago
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