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qaws [65]
3 years ago
9

HELP help peardeck one question

Mathematics
1 answer:
solmaris [256]3 years ago
6 0

Answer:

Step-by-step explanation:

=x^2-x+3+3x^2-3x+2

=5x^2-4x+5

You might be interested in
Create 3 different fractions that are equivalent to 0
Alexeev081 [22]

Answer:

0/2.  0/9.  0/78

Step-by-step explanation:

Anything with a numerator of zero will equal zero.

I hope this helped :D

5 0
3 years ago
Read 2 more answers
A quadratic equation has the zeros –3 and 6. Which quadratic equation can be the given equation?
Svetach [21]

Answer:

Answer:

It can be A. (not B or C)

Step-by-step explanation:

It is A because x-6=0 can be simplified to x=6. Then, 2x + 6, you can divide the whole equation resulting in x+3=0, simplify this and you get x=-3. YES

It is not B because, while x+3=0 results in a zero of -3, 6x-1 can be simplified to be divided by 6. When we do this we get x-1/6=0, which is not equivalent to 6. NO

It is not C because, while x-6=0 results in a zero of 6, -3x can be simplified with the zero product property to get -3x=0 then dividing -3 by 0 giving you 0 which is not equivalent to one. NO

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jamie ordered 24 combo meals for $5 each for a party. The service charge for home delivery for the whole purchase was $6.
Agata [3.3K]
It's easy you do 24 times 5 and then find out the service charge by dividing ratios between the meal and parties and then add 6$ to your total!
7 0
3 years ago
Muffins come in 3 sizes, 4 flavors, and with or without nut toppings. How many combinations are in the sample space?
oksano4ka [1.4K]

Answer:

9 combinations are in the sample space

Step-by-step explanation:

Well there's 3 sizes 4 flavors and with or without nuts

3(Sizes)+ 4(flavors)+ 2(with or without)

Therefor when you add those up you get 9 things people can choose from, known as the sample space.

3 0
3 years ago
What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
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