Answer:
80 labels
Step-by-step explanation:
The number of packages are 16 envelopes and 20 envelopes
We solve using LCM Method
We find the Multiples of 16 and 20
Multiples of 16:
16, 32, 48, 64, 80, 96, 112
Multiples of 20:
20, 40, 60, 80, 100, 120
Therefore,
LCM(16, 20) = 80
The least number of labels and envelopes you can buy so that there is one label on each envelope with none left over = 80 labels
It would be y=(x+4)²+9.
To complete the square, we divide the value of b, the coefficient of x, by 2 and square it:
(8/2)² = 4² = 16
We would add 16 to this in order to have a perfect square; but we would also need to subtract 16 at the end to keep it equal. This would give us:
y=(x²+8x+16)+25-16
y = (x+4)² + 9
Squares,rectangles,parallelograms. would be quadrilaterals.
I’ve never seen it done that way but I would say it’s 32 / 4 = 8
Collectively, there are 32 squares, separated into groups of 4. When you divide 32 by 4, you’re left with 8 which is reflected by the 8 blue ovals
<h3>
Answer:</h3><h3>
-3.5,-0.5</h3>
Step-by-step explanation:
