Question

Help with these 3 I did all the other questions of the assignment, these are confusing ASAP

Answer 1

Answers:

• Problem 7) 25.2 feet
• Problem 8) Angle = 52 degrees;  Distance = 14.3 feet
• Problem 9) DE = 22, EC = 10, BC = 20

=====================================================

Explanation:

The diagrams for problems 7 and 8 are shown below.

------------------------------------

Problem 7

Apply the tangent ratio to find that...

tan(angle) = opposite/adjacent

tan(42) = x/28

28*tan(42) = x

x = 28*tan(42)

x = 25.2113132403396

x = 25.2

Make sure your calculator is in degree mode. One way to check is to type in tan(45) and you should get 1 as a result.

------------------------------------

Problem 8, part 1

To find the angle y, we must use the sine ratio

sin(angle) = opposite/hypotenuse

sin(y) = 18/23

y = arcsin(18/23)

y = 51.5000495907521

y = 52 degrees approximately

------------------------------------

Problem 8, part 2

We can use the pythagorean theorem to find the missing side x

a^2+b^2 = c^2

18^2+x^2 = 23^2

324+x^2 = 529

x^2 = 529-324

x^2 = 205

x = sqrt(205)

x = 14.3178210632763

x = 14.3

Or alternatively, we can apply the tangent ratio on the angle y we found earlier to help find x

tan(angle) = opposite/adjacent

tan(y) = 18/x

tan(51.50004959) = 18/x

x*tan(51.50004959) = 18

x = 18/tan(51.50004959)

x = 14.3178210636621

x = 14.3

------------------------------------

Problem 9

The double tickmarks show that BE = EC = 10. That means BC = BE+EC = 10+10 = 20.

Since we have similar triangles, we can solve for x like so

DE/AC = BE/BC

x/44 = 10/20

20x = 44*10

20x = 440

x = 440/20

x = 22

So DE is 22 units long. Note how this is half as long as the side AC = 44.