Answer:
C. -3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-7x + 6 = 27
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Subtraction Property of Equality] Subtract 6 on both sides: -7x = 21
- [Division Property of Equality] Divide -7 on both sides: x = -3
The area of the triangle will be 24912 sq. units. Square units and other similar units are used to measure area.
<h3>What is the area?</h3>
The space filled by a flat form or the surface of an item is known as the area.
The number of unit squares that cover the surface of a closed-form is the figure's area.
For:
(X1, Y1) = (1, 15)
(X2, Y2) = (-2, 1)
d = 14.317821
For:
(X₂, Y₂) = (-2, 1)
(X₃, Y₃) = (4, 5)
d = 7.211103
For applying the pythogorous them we need the right angle triangle obtained by bisect from the mid point.
The value of the base is;
⇒7.2 / 2
⇒3.6
apply the pythogorous theorem for finding the height;
h² = p² + b²
14.31² = p² + 3.6²
p = 13.84
The area of the triangle is;

Hence, the area of the triangle will be 24912 sq. units.
To learn more about the area, refer to the link;
brainly.com/question/11952845
#SPJ1
The area is found by base x height
To find the missing height in the first one you divide 147 by 15 3/4 and get 9 1/3.
To find the missing base in the second one you divide 140 5/8 by 11 1/4 and get 12 1/2.
To find the missing height in the third one you divide 151 3/16 by 10 1/4 and get 14 3/4.
Make me brainliest ! :)
Answer:
<h2>x = 35</h2>
Step-by-step explanation:
Because the angles are vertical angles, they must be equal.
3x + 7 = 112
3x = 105
x = 35
Check
3(35) + 7 = 112
112 = 112 Correct
Answer:

Step-by-step explanation:
Let,
= y
sin(y) = 


---------(1)


cos(y) = 
= 
= 
Therefore, from equation (1),

Or ![\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7Bx%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7Bx%5E2%7D%7B36%7D%7D%7D)
At x = 4,
![\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B4%7D%7B6%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B4%5E2%7D%7B36%7D%7D%7D)
![\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5B%5Ctext%7Bsin%7D%5E%7B-1%7D%28%5Cfrac%7B2%7D%7B3%7D%29%5D%3D%5Cfrac%7B1%7D%7B6%5Csqrt%7B1-%5Cfrac%7B16%7D%7B36%7D%7D%7D)



