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Furkat [3]
3 years ago
14

Please help i’ll give brainliest please tysm :))

Mathematics
1 answer:
natima [27]3 years ago
5 0

Answer:

Grape juice has 180 containers.

Step-by-step explanation:

Given that the ratio of containers of orange juice to containers of grape juice in a store is 5 orange juices to 4 grape juices.

i.e.

Orange Juice containers : Grape Juice containers = 5 : 4

Total containers = 405

It means if we divide 405 by 9, we get the 9 equal parts of 45.

i.e. 405 / 9 = 45

as

Orange Juice containers : Grape Juice containers = 5 : 4

It means the share of Grape Juice containers is 4 parts out of 9 parts.

Thus, multiply 45 by 4 to determine the number of containers grape juice have:

45 × 4 =  180 containers

Therefore, grape juice has 180 containers.

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A. Ha: p < 0.3

Using the significance level for example \alpha=0.05 we see that p_v>\alpha so we have enough evidence at this significance level to FAIL to reject the null hypothesis. And on this case we can say that the proportion of employees that received the merit raise are African American  is not significantly less than 0.3 or 30%.

Step-by-step explanation:

1) Data given and notation

n=60 represent the random sample taken  

X=17 represent the employees that received the merit raise are African American

\hat p=\frac{17}{60}=0.283 estimated proportion of employees that received the merit raise are African American

p_o=0.3 is the value that we want to test  

\alpha represent the significance level (no given)  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

p= population proportion of employees that received the merit raise are African American

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of employees that received the merit raise are African American is less than 0.3 or 30%. :  

Null Hypothesis: p \geq 0.3

Alternative Hypothesis: p

A. Ha: p < 0.3

We assume that the proportion follows a normal distribution.  

This is a one tail lower test for the proportion of employees that received the merit raise are African American .

The One-Sample Proportion Test is "used to assess whether a population proportion \hat p is significantly (different,higher or less) from a hypothesized value p_o".

<em>Check for the assumptions that he sample must satisfy in order to apply the test </em>

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np_o =60*0.3=18>10

n(1-p_o)=60*(1-0.3)=42>10

3) Calculate the statistic  

The statistic is calculated with the following formula:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}

On this case the value of p_o=0.3 is the value that we are testing and n = 60.

z=\frac{0.283 -0.3}{\sqrt{\frac{0.3(1-0.3)}{60}}}=-0.287

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

Based on the alternative hypothesis the p value would be given by:

p_v =P(Z  

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