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Salsk061 [2.6K]
3 years ago
13

HELP PLEASEEE!!

Mathematics
1 answer:
Luden [163]3 years ago
8 0

\left[\begin{array}{ccc}2&6&3\\-5&1&4\end{array}\right]

R1 ÷ 2  = \left[\begin{array}{ccc}1&3&1.5\\-5&1&4\end{array}\right]

R2 ÷ -5 = \left[\begin{array}{ccc}1&3&1.5\\1&-0.2&-0.8\end{array}\right]

R2: R1 - R2  = \left[\begin{array}{ccc}1&3&1.5\\0&3.2&2.3\end{array}\right]

R2 ÷ 3.2 =  \left[\begin{array}{ccc}1&3&1.5\\0&1&0.71875\end{array}\right]

R1: R1 - 3R2 = \left[\begin{array}{ccc}1&0&0.65625\\0&1&0.71875\end{array}\right]

Answer: x = 0.65625, y = 0.71875

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3 years ago
Find the projection of u = &lt;–6, –7&gt; onto v = &lt;1, 1&gt; a. &lt;-13/2,-13/2&gt; b. &lt;39,91/2&gt; c. &lt;-13/1764,-13/17
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<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

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v = <1, 1>

These can be re-written in unit vector notation as;

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<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

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u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

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<em>Substitute these values into equation (i) as follows;</em>

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3 years ago
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GuDViN [60]

Answer:

G.

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therefore, option G. table G. is the correct answer

try doing the ratio and proportion on the other table and the number of cards DO NOT match with the amount.  (see attached)

7 0
3 years ago
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