All categories

3 years ago

Function f is shown on the graph. What is the range of f?

Mathematics

1 answer:

solong [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Honestly, I’m not sure, but it’s the only one that made the most sense to me.

Hopefully This Helps, good luck!

You might be interested in

Keisha is making potato casserole

lord [1]

Answer:

4 1/2 I think

Step-by-step explanation:

I think but I'm not for sure

4 0

3 years ago

in a particular class of 23 students, 18 are men. what fraction of the students in the class are men?k

Mademuasel [1]

It gave you the answer for men they said their were 18 men out of 23 so are they asking for women or actually men cause if it was that it would be 18/23

7 0

3 years ago

Mort is trying to save money to get out of student debt he saves money each month from his paycheck the function below relates m

Savatey [412]

Answer:

hello your answer is 21 y=21

Step-by-step explanation:

3 times -7 is 21- hope i helped

7 0

3 years ago

Please Do These Three Equations And Show Work

german

2) Add 0.1 to both sides. v/2.2=7.5

Then multiply by 2.2 on both sides.

v=16.5

4) Subtract 1.9 from both sides. -1.3g=-13

Divide both sides by -1.3

g=10

6) Add 1.4 to both sides. -12.9=-3d

Divide -3 on both sides.

d=4.3

3 0

3 years ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

3 years ago