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matrenka [14]
3 years ago
13

Function f is shown on the graph. What is the range of f?

Mathematics
1 answer:
solong [7]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Honestly, I’m not sure, but it’s the only one that made the most sense to me.

Hopefully This Helps, good luck!

You might be interested in
Plz help quick i will mark u brainiest its about transishons
saveliy_v [14]

Answer:

(x,y) --> (x+4, y-5)

Step-by-step explanation:

A is correct. B can be represented as x+4, y - 5 because the x values shifted 4 to the right (a positive shift so x+4) and the y values shifted 5 down (a negative shift so y-5)

6 0
3 years ago
What is the sum of the zeros of the function: y= x^2 - 5x + 6?
yawa3891 [41]

Answer:

Step-by-step explanation:

The zeros are the values of x for which y = 0

Quadratic formula

x = [5 ± √(5² – 4·1·6)] / [2·1]

 = [5 ± √1] / 2

 = [5 ± 1] /2

 = 2, 3

sum of zeros = 5

7 0
3 years ago
PLEASE HELP THIS IS A MAJOR GRADE! In the diagram below, triangle DEF is a translation of triangle ABC.
Marizza181 [45]

Answer:

2 units right and 5 units down

3 0
2 years ago
Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x
AfilCa [17]

Answer:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0
1 year ago
5. h(x)=0.5x - 1 with domain (-♾, 4) what is the range
Rudiy27

We have a domain of a function, that is, which x-es can we throw in. But we are asking which y-s will we get given that we can only throw x-es in (-\infty,4).

Let's try x=4 even though we are forbidden to put 4 inside h we are still able to do so.

So h(4)=0.5\cdot4-1=2-1=1 what we just got is the upper limit of the range. The lower limit is h(-\infty)=-\infty.

So the range is just (-\infty, 1).

Hope this helps :)

6 0
3 years ago
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