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statuscvo [17]
3 years ago
12

Please help .. with this.. it’s math.. asap

Mathematics
2 answers:
sweet [91]3 years ago
8 0
I’m pretty sure it’s D
alekssr [168]3 years ago
4 0
Option D. ..........………
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Step-by-step explanation:


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Step-by-step explanation:


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Answer the question with explanation;​
PSYCHO15rus [73]

Answer:

The statement in the question is wrong. The series actually diverges.

Step-by-step explanation:

We compute

\lim_{n\to\infty}\frac{n^2}{(n+1)^2}=\lim_{n\to\infty}\left(\frac{n^2}{n^2+2n+1}\cdot\frac{1/n^2}{1/n^2}\right)=\lim_{n\to\infty}\frac1{1+2/n+1/n^2}=\frac1{1+0+0}=1\ne0

Therefore, by the series divergence test, the series \sum_{n=1}^\infty\frac{n^2}{(n+1)^2} diverges.

EDIT: To VectorFundament120, if (x_n)_{n\in\mathbb N} is a sequence, both \lim x_n and \lim_{n\to\infty}x_n are common notation for its limit. The former is not wrong but I have switched to the latter if that helps.

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3 years ago
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Step-by-step explanation:

Can you mark me as brainliest

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