Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}
Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number
Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}
Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}
Base 14 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D}
The digit D is the largest single digit of that last set. So the largest 3-digit base 14 integer is DDD which is the final answer
Note: It is similar to how 999 is the largest 3-digit base 10 integer
Step-by-step explanation:
remember. the radius is always half the diameter.
volume of a cylinder
pi × r² × height
pi×7.5²×48 = pi×56.25×48 = 8,482.300165... in³
volume of a sphere
4/3 × pi × r³
and that volume should be the same as the cylinder. so,
4/3 × pi × r³ = pi×56.25×48
4/3 × r³ = 56.25 × 48
1/3 × r³ = 56.25 × 12
r³ = 56.25 × 36 = 7.5² × 6² = (7.5×6)² = 45² = 2025
![r = \sqrt[3]{2025}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B2025%7D%20)
which would be 12.65148998... in.