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tensa zangetsu [6.8K]
3 years ago
5

What is the equation of the line that passes through (5,-3) and (3,7)

Mathematics
1 answer:
Sliva [168]3 years ago
6 0

Answer:

-5x +22

Step-by-step explanation:

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Let f(x)=cos(x)x^-2<br> F’(x)=
kondaur [170]

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

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AleksAgata [21]

9514 1404 393

Answer:

  16 square units

Step-by-step explanation:

When you plot the points, you see they define a trapezoid with bases of lengths 2 and 6, and a height of 4. The area formula is ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(2 +6)(4) = 16

The area of the trapezoid is 16 square units.

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