The probability of type II error will decrease if the level of significance of a hypothesis test is raised from 0.005 to 0.2.
<h3 /><h3>What is a type II error?</h3>
A type II error occurs when a false null hypothesis is not rejected or a true alternative hypothesis is mistakenly rejected.
It is denoted by 'β'. The power of the hypothesis is given by '1 - β'.
<h3>How the type II error is related to the significance level?</h3>
The relation between type II error and the significance level(α):
- The higher values of significance level make it easier to reject the null hypothesis. So, the probability of type II error decreases.
- The lower values of significance level make it fail to reject a false null hypothesis. So, the probability of type II error increases.
- Thus, if the significance level increases, the type II error decreases and vice-versa.
From this, it is known that when the significance level of the given hypothesis test is raised from 0.005 to 0.2, the probability of type II error will decrease.
Learn more about type II error of a hypothesis test here:
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Answer:
1197.9
Step-by-step explanation:
10 percent of 1331 is 133.1.
because its 10 percent more, you need to do 1331-133.1:)
Step-by-step explanation:
<u>Given</u>
- x + 2y = 3 and xy = 2
- show that x³ + 8y³ + 9 = 0
<u>Solution in steps:</u>
- (x + 2y)³ = 3³
- x³ + 3x²(2y) + 3x(2y)² + (2y)³ = 27
- x³ + 6x(xy) + 12y(xy) + 8y³ = 27
- x³ + 8y³ + 6(x + 2y)xy = 27 ⇒ Substitute values
- x³ + 8y³ + 6*3*2 = 27
- x³ + 8y³ + 36 - 27 = 0
- x³ + 8y³ + 9 = 0
Done
yes because you need to do this then you need to do that and plus yeah you right
