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2 years ago

Evaluate x(–y + z) for x = 3, y = 3, and z = 1.

Mathematics

2 answers:

Nookie1986 [14]2 years ago

8 0

Answer:

3(-3+1)=

3(-2)=

-6

Answer is - 6

Kazeer [188]2 years ago

7 0

The answer is -8. 3 x -3 = -9 + 1 = -8

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Please help with A,B for 10 points.

denis-greek [22]

Answer:

y= (C -Ax)/B

x= (C -By)/A

Step-by-step explanation:

Ax+ By = C

solve for y

Subtract AX from each side

Ax+ By - Ax = C-Ax

By = C -Ax

Divide by B

By /B= (C -Ax)/B

y= (C -Ax)/B

solve for x

Subtract By from each side

Ax+ By - By = C-By

Ax = C -By

Divide by A

Ax/A= (C -By)/A

x= (C -By)/A

4 0

2 years ago

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Can someone turn 1938 into a scientific notation for me? 10 POINTS

photoshop1234 [79]

Answer:

1.938 x 10^3

Step-by-step explanation:

1938 move decimal 3 times to left and times by 10 to 3rd

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2 years ago

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I'm unsure of what the answer to this is, I need help.

Zigmanuir [339]

Answer:

I think it would be A

Step-by-step explanation:

Because 9/6 is 1.5 and when you do 3/2 it is also 1.5.

I hope this helps

4 0

3 years ago

Can somebody explain to me how to do this and the answers and how you got it

yaroslaw [1]

7. Easiest method is substitution. Since y=x/2, then:
2x+3(x/2)=28
8.Substituting again, we get:
3x-6x=6
-3x=6
x=-2
(-2,6)
☺☺☺☺

6 0

3 years ago

A waitress sold 11 ribeye steak dinners and 12 grilled salmon dinners, totaling $560.63 on a particular day. Another day she s

Eduardwww [97]

The cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

Solution:

Let "a" be the cost of each ribeye steak dinners

Let "b" be the cost of each grilled salmon dinners

A waitress sold 11 ribeye steak dinners and 12 grilled salmon dinners, totaling $560.63 on a particular day

Thus we frame a equation as:

11 x cost of each ribeye steak dinners + 12 x cost of each grilled salmon dinners = 560.63

$11 \times a + 12 \times b = 560.63$

11a + 12b = 560.63 -------- eqn 1

Another day she sold 16 ribeye steak dinners and 6 grilled salmon dinners, totaling $584.46

Thus we frame a equation as:

16 x cost of each ribeye steak dinners + 6 x cost of each grilled salmon dinners = 584.46

$16 \times a + 6 \times b = 584.46$

16a + 6b = 584.46 ------------ eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 2 by 2

32a + 12b = 1168.92 ------- eqn 3

Subtract eqn 1 from eqn 3

32a + 12b = 1168.92

11a + 12b = 560.63

( - ) ----------------

21a = 1168.92 - 560.63

21a = 608.29

Divide both sides by 21

$a = 28.96 \approx 29$

Substitute a = 29 in eqn 1

11(29) + 12b = 560.63

319 + 12b = 560.63

12b = 560.63 - 319

12b = 214.63

Divide both sides by 12

$b = 20.13 \approx 20$

Thus cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

5 0

3 years ago