Just sayin' you shouldn't use up all ur points on one question
Answer:
Number of dimes = 16
Number of quarters = 17
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Work Shown:
d = number of dimes
q = number of quarters
d+q = 33 coins total, this solves to d = 33-q
10d = value of all the dimes in cents
25q = value of all the quarters in cents
10d+25q = 585 cents total
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Plug in d = 33-q and solve for q
10d+25q = 585
10(33-q) + 25q = 585
330-10q+25q = 585
15q+330 = 585
15q = 585-330
15q = 255
q = 255/15
q = 17
The man has 17 quarters
d = 33-q = 33-17 = 16
He also has 16 dimes.
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Check:
16 dimes + 17 quarters = 33 coins total
16 dimes = 16*10 = 160 cents
17 quarters = 17*25 = 425 cents
160 cents + 425 cents = 585 cents
The answer is confirmed.
Answer:
Isosceles
Step-by-step explanation:
In order to figure what type of triangle this is out, we need to start by plotting the given points. That will help us visualize the triangle better and see if our conclusions make sense. (See attached picture).
Once we got the triangle, the strategy to follow is to use the distance between two points formula to see what the measurement of each side of the triangle is. This will help us determine if 2, 3 or none of the sides of the tirangle are the same.
The distance formula is the following:
![distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}](https://tex.z-dn.net/?f=distance%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D)
so now we can find the desired distances, let's start with the distance between P and Q:
![|PQ|=\sqrt{(-4-0)^{2}+(9-8)^{2}}](https://tex.z-dn.net/?f=%7CPQ%7C%3D%5Csqrt%7B%28-4-0%29%5E%7B2%7D%2B%289-8%29%5E%7B2%7D%7D)
which yields:
![|PQ|=\sqrt{17}](https://tex.z-dn.net/?f=%7CPQ%7C%3D%5Csqrt%7B17%7D)
next, let's find the distance between P and R:
![|PR|=\sqrt{(-4-(-3))^{2}+(9-5)^{2}}](https://tex.z-dn.net/?f=%7CPR%7C%3D%5Csqrt%7B%28-4-%28-3%29%29%5E%7B2%7D%2B%289-5%29%5E%7B2%7D%7D)
which yields:
![|PR|=\sqrt{17}](https://tex.z-dn.net/?f=%7CPR%7C%3D%5Csqrt%7B17%7D)
and finally the distance between Q and R:
![|QR|=\sqrt{(0-(-3))^{2}+(8-5)^{2}}](https://tex.z-dn.net/?f=%7CQR%7C%3D%5Csqrt%7B%280-%28-3%29%29%5E%7B2%7D%2B%288-5%29%5E%7B2%7D%7D)
which yields:
![|QR|=3\sqrt{2}](https://tex.z-dn.net/?f=%7CQR%7C%3D3%5Csqrt%7B2%7D)
As you may see from the result, only two of the three sides are the same, |PQ| and |PR|, so this will be an Isosceles triangle.
Answer:
1
Step-by-step explanation:
{36 ÷ (-9)} ÷ {(-24) ÷ 6}
= (-4) ÷ (-4)
= 1
A=pi(r)squared
d=5
r=2.5
A= 2.5(2.5)(pi)
Area= 6.25