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3 years ago

Calculate the remainder when 3456 is divided by 7

Mathematics

1 answer:

lianna [129]3 years ago

7 0

Answer:

The remainder when 3456 is divided by 7 is 6.

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4 years ago

Multiplying and dividing radical expressions and leaving them in factored form. I am trying to find the best and easy way to get

natka813 [3]

Answer:

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}$

Step-by-step explanation:

Given

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27}$

Required

Solve

Change / to *

$\frac{3x + 8}{36 - 2x} * \frac{3x^2 - 27}{27x^2 + 72x}$

Factor out 3

$\frac{3x + 8}{36 - 2x} * \frac{3(x^2 - 9)}{3(9x^2 + 24x)}$

$\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{(9x^2 + 24x)}$

Factorize:

$\frac{3x + 8}{36 - 2x} * \frac{(x^2 - 9)}{3x(3x + 8)}$

Cancel out 3x + 8

$\frac{1}{36 - 2x} * \frac{(x^2 - 9)}{3x}$

Factorize:

$\frac{1}{2(18 - x)} * \frac{(x^2 - 9)}{3x}$

Combine

$\frac{x^2 - 9}{2*3x(18 - x)}$

$\frac{x^2 - 9}{6x(18 - x)}$

Express the numerator as a difference of two squares

$\frac{(x - 3)(x+3)}{6x(18 - x)}$

Hence:

$\frac{3x + 8}{36 - 2x} / \frac{27x^2 + 72x}{3x^2 - 27} = \frac{(x - 3)(x+3)}{6x(18 - x)}$

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Interest is compounded semianually. Find the amount in the account after the given time.

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Answer:

Step-by-step explanation:

Compound Interest Formula :

A = P (1 + r/n)^(nt)

A = amount
P = principal
r = rate (in decimals)
n = number of times compounded
t = number of years

Solving :

A = (1,000)(1 + 0.05/2)²⁽³⁾
A = (1,000)(1.025)⁶
A = (1,000)(1.15969342)
A = <u>$1,159.69</u>

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