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3 years ago

Becky can wash 15 dishes in 5 minutes. How many dishes will she be able to wash in 8 minutes?

Mathematics

2 answers:

lbvjy [14]3 years ago

6 0

Answer:

24 plates

Step-by-step explanation:

If she can wash 15 dishes in 5 minutes you just need to figure out how many dished she can washe in 1 minute. so you are gonna divide 15 by 5 and get 3 because 3 times 5 equals 15. so then that means she can wash 3 plates in 1 minute. so if she washed 15 in 5 in 6 minutes she can wash 18 and in 7 minutes she can wash 21 and in 8 minutes she can wash 24. Your just adding 3 to the 15 for every minute.

bixtya [17]3 years ago

5 0

Answer:

24 is correct answer

Step-by-step explanation:

its a 5:15 ratio, you are finding 8:x

8/5=1.6-> 1.6 x a5 = 24

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Answer:

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3 years ago

5. A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4pci or less. Th

zysi [14]

Complete Question

A scientist believes the concentration of radon gas in the air is greater that the established safe level of 4 pci or less. The scientist tests the composition for 36 days finding an average concentration of 4.4 pci with a sample standard deviation of 1 pci.

a) In testing the scientist's belief, write the appropriate hypotheses:

$H_o:$ Ha:

b) What decision should be made?

Answer:

The null hypothesis is $H_o : \mu \le 4 \ pci$

The alternative hypothesis is $H_a : \mu > 4 \ pci$

There is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 4 \ pci$

The sample size $n = 36 \ days$

The sample mean is $\= x = 4.4 \ pci$

The standard deviation is $\sigma = 1 \ pci$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu = 4 \ pci$

The alternative hypothesis is $H_a : \mu > 4 \ pci$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu }{ \frac{ \sigma}{ \sqrt{n} } }$

=> $t = \frac{ 4.4 - 4 }{ \frac{ 1}{ \sqrt{36} } }$

=> $t =2.4$

The p-value is mathematically represented as

$p-value = P(Z > 2.4 )$

From the z-table

$P(Z > 2.4 ) = 0.008$

$p-value =0.008$

So from this obtained value we see that

$p-value < \alpha$ so we reject the null hypothesis

Hence we can conclude that there is sufficient evidence to conclude that the concentration of radon gas in the air is greater that the established safe level of 4pci or less

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