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maxonik [38]
3 years ago
9

Write an equation in point-slope form and slope-intercept form for each line

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:5.987

Step-by-step explanation:

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4+2+x and (4+2)+x are equivalent.
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Which defines a circle?
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the last one

all coplanar points equidistant from a given point.

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Please answer
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A. 3.

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Bob bought a broken motor scooter, repaired it, and sold the scooter for $130. That was $50 less than 1.5 times what he paid for
FromTheMoon [43]

Answer: $120

Step-by-step explanation:

Assume the original price is x.

He sold the scooter for $130 and this was $50 less than 1.5 times what he paid for it.

Relevant formula is therefore:

1.5x - 50 = 130

1.5x = 130 + 50

x = 180/1.5

x = $120

4 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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