Question

Suppose that all edges of this A-frame house measure 6.5 yards, and the height of the house is 5.6 yards.

Answer 1

Answer:

Outer surface area of this house = 187.85 yards²

Explanation:

Given:

Side = 6.5 yards

Height = 5.6 yards

Find:

Outer surface area of this house

Computation:

Outer surface area of this house = 2[lb + bh + hl] - lb

Outer surface area of this house = 2[(6.5)(6.5) + (6.5)(5.6) + (5.6)(6.5)] - (6.5)(6.5)

Outer surface area of this house = 2[42.25 + 36.4 + 36.4] - 42.25

Outer surface area of this house = 2[115.05] - 42.25

Outer surface area of this house = 187.85 yards²