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4 years ago

I NEED HELP ASAP!! Subtract. -30-27= ? -5-(-4)= ?

1 answer:

5 0

-30-27= -57
When both numbers are negative, they are “added” in a sense, but remain negative.

-5-(-4)= -1
You have to multiply the (-4) by the “invisible” -1 on the outside before you add/subtract.

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3 years ago

673.5 in scientific notation

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4 years ago

I do not understand any of the questions its asking :c

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Answer:

Step-by-step explanation:

The total number of students is 350 + 50 + 225 + 375 = 1000.

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There are 350 students in choir only, as well as 50 students in both choir and band. So there are 400 students in choir, 50 of whom are also in band. So the probability is 50/400, or 12.5%.

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3 years ago

In an examination

aleksandr82 [10.1K]

Answer:

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3 years ago

Simplify 6/2√3-√6+√6/√3+√2- 4√3/√6-√2

kkurt [141]

Answer:

-sqrt(2) + 3 sqrt(3) - sqrt(6)

Step-by-step explanation:

Simplify the following:

(6 sqrt(3))/2 - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6/2 = (2×3)/2 = 3:

3 sqrt(3) - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (sqrt(6))/(sqrt(3)) = (sqrt(6))/(sqrt(3))×(sqrt(3))/(sqrt(3)) = (sqrt(6) sqrt(3))/3:

3 sqrt(3) - sqrt(6) + (sqrt(6) sqrt(3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(6) sqrt(3) = sqrt(6×3):

3 sqrt(3) - sqrt(6) + (sqrt(6×3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6×3 = 18:

3 sqrt(3) - sqrt(6) + (sqrt(18))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + (3 sqrt(2))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

(3 sqrt(2))/3 = 3/3×sqrt(2) = sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (-4 sqrt(3))/(sqrt(6)) = (-4 sqrt(3))/(sqrt(6))×(sqrt(6))/(sqrt(6)) = (-4 sqrt(3) sqrt(6))/6:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-4 sqrt(3) sqrt(6))/6 - sqrt(2)

The gcd of -4 and 6 is 2, so (-4 sqrt(3) sqrt(6))/6 = ((2 (-2)) sqrt(3) sqrt(6))/(2×3) = 2/2×(-2 sqrt(3) sqrt(6))/3 = (-2 sqrt(3) sqrt(6))/3:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-2 sqrt(3) sqrt(6))/3 - sqrt(2)

sqrt(3) sqrt(6) = sqrt(3×6):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 sqrt(3×6) - sqrt(2)

3×6 = 18:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (2 sqrt(18))/3 - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 3 sqrt(2) - sqrt(2)

Combine powers. (-2×3 sqrt(2))/3 = 2 sqrt(2)×3^(1 - 1) (-1):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^(1 - 1) - sqrt(2)

1 - 1 = 0:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^0 - sqrt(2)

3^0 = 1:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×1 - sqrt(2)

Add like terms. 3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2) - sqrt(2) = -sqrt(2) + 3 sqrt(3) - sqrt(6):

Answer: -sqrt(2) + 3 sqrt(3) - sqrt(6)

7 0

4 years ago