36 actually, I counted it myself
I could be very much wrong but maybe 45 cm3
Answer:
Step-by-step explanation:
![\sf = 49y^2+42y+9\\\\=(7y)^2+2(7y)(3)+(3)^2\\\\Using \ Formula \ a^2+2ab+b^2 = (a+b)^2\\\\= (7y+3)^2\\\\= (7y+3)(7y+3)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%3D%2049y%5E2%2B42y%2B9%5C%5C%5C%5C%3D%287y%29%5E2%2B2%287y%29%283%29%2B%283%29%5E2%5C%5C%5C%5CUsing%20%5C%20Formula%20%5C%20a%5E2%2B2ab%2Bb%5E2%20%3D%20%28a%2Bb%29%5E2%5C%5C%5C%5C%3D%20%287y%2B3%29%5E2%5C%5C%5C%5C%3D%20%287y%2B3%29%287y%2B3%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Table B. The same input can't go to different outputs
Answer:
(1, 4) and (1,3), because they have the same x-value
Step-by-step explanation:
For a relation to be regarded as a function, there should be no two y-values assigned to an x-value. However, two different x-values can have the same y-values.
In the relation given in the equation, the ordered pairs (1,4) and (1,3), prevent the relation from being a function because, two y-values were assigned to the same x-value. x = 1, is having y = 4, and 3 respectively.
Therefore, the relation is not a function anymore if both ordered pairs are included.
<em>The ordered pairs which make the relation not to be a function are: "(1, 4) and (1,3), because they have the same x-value".</em>
