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VMariaS [17]
4 years ago
13

Simplify using order of operations: (5 – 2) + 23.

Mathematics
2 answers:
Phoenix [80]4 years ago
6 0
Step 2: 3+23
The answer is 26
Rudik [331]4 years ago
5 0
The answer is 25 but i can't exactly show how


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The floor of the cage measures 11 yardyard wide by 66 feetfeet long. One bag of shavings covers 55 square feetfeet. How many bag
bazaltina [42]

Answer:

3 3/5 bags

Step-by-step explanation:

We have to find the surface area of the floor of the cage first.

The cage measures 1 yard wide by 6 feet long.

1 yard = 3 feet

The floor of the cage is rectangular, so, the surface area of the floor of the cage is therefore:

3 * 6 = 18 square feet

One bag of shavings covers 5 square feet.

To find the number of bags we need to cover the floor, we divide the surface area of the floor by the number of bags per square feet.

The number of bags needed for the floor of the cage is therefore :

18 / 5 = 3 3/5 bags

5 0
4 years ago
Which exponential function is represented by the graph?
Anna [14]

Answer:

Step-by-step explanation:

Let's solve this using our formula for exponential functions:

y=a(b)^x where a is the initial value and b is the growth/decay rate. We will fill that equation in with 2 of the coordinates on the graph and come up with the values for both a and b. (0, 3) and (1, 6):

3=a(b)^0. Anything raised to the power of 0 is 1, so that means that

a = 3. We will use that value along with the x and y from the second coordinate to solve for b:

6=3(b)^1. b to the first is just b, so our equation is

6 = 3b and

b = 2.

Our equation then is

y=3(2)^x, the third choice down.

8 0
3 years ago
(7,-1) and ( 21,-5) what is the slope
mart [117]

Answer:

-2/7

Step-by-step explanation:

Going from (7,-1) to ( 21,-5) we see x (the 'run') increasing by 14 and y (the 'rise') decreasing by 4.  Thus, the slope of the line connecting these two points is m = rise/run = -4/14, or -2/7.

8 0
3 years ago
Which expression is equivalent to 3/5 (5n-12) -1/4 (3n +16)
natita [175]
Hopefully you will be enlighted more than confused

4 0
3 years ago
A hunter is at a point on a riverbank. He wants to get to his cabin located 2 Miles North and 8 Miles West. He can travel 5 Mph
miskamm [114]

Answer:

Option A

Step-by-step explanation:

A hunter travels to his cabinet located at 2 Miles North and 8 Miles West.

Let "d" be the distance traveled before reaching the rocky ground at point say "P". Let the cabin be at "C"

The distance between C and P is given by

\sqrt{(2^2+(8-d)^2}\\

Let "t" be the time taken to travel distance CP.

T = \frac{d}{5} + \frac{\sqrt{2^2+(8-d)^2} }{3}

Minimum time will be when "t" is equal to zero

Differentiating the above equation wrt "d", we get -

= \frac{1}{5} + \frac{1}{3} (\frac{-2(8-d)}{2\sqrt{2^2+(8-d)^2} } )= 0\\\frac{1}{5} = \frac{1}{3} \frac{(8-d)}{\sqrt{4+(8-d)^2} } \\3\sqrt{4+64+d^2-16d} = 40-5d\\

On squaring both the sides , we get -

3\sqrt{4+64+d^2-16d} = 40-5d\\9(68+d^2-16d)= 1600+25d^2 -400d\\612+9d^2-144d=1600+25d^2 -400d\\16d^2-256d+988=0\\d_1 = 9.5\\d_2 = 6.5

"d" cannot be greater than 8 miles.

Hence, the value of "d" is equal to 6.5

Option A

8 0
3 years ago
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