Which cell division phase is shown in the image?
2 answers:
You might be interested in
There 2 ways to solve this
1- Directly :
80% of water in the fresh berries è 20% of water in the dried berries
36 Ibs of the fresh berries è X Ibs of the dried berries
X = <span> = 9 Ibs</span>
<span>2- </span>If you do not understand the first method, the second one is more explicit:
First, we gonna calculate the weight of the berries without water (dehydrated):
<span>36 * 80% = 28.8 Ibs (of water in the berries)</span>
Then:
<span>36 – 28.8 = 7.2 Ibs (of completely dehydrated berries)</span>
Next, we gonna add 20% of water in the dehydrated berries:
X (total weight of dried berries) è 100%
7.2 Ibs of dehydrated berries è 80%
X = <span> </span> = 9 Ibs
Answer:
d) 2v
Explanation:
Since, root mean square speed of a molecule,
Where,
k = Boltzmann constant,
T = temperature of gas,
m = mass of molecule,
Also, the temperature of a gas,
Where,
p = pressure of the gas,
V = volume,
n = number of moles of gas,
R = universal gas constant,
If V = 2V and p = 2P
Then,
Hence, if rms speed of a gas molecule under initial conditions is v then rms speed of a molecule will be 2v
i.e. option d is correct.